標題:
數學 complex number
發問:
simplify {[(cis^12)(3x)][(cis^25) (-2x)]}/{[(cis^27)(x/3)][(cis^44) (-x/2)]]}
最佳解答:
{[(cis^12)(3x)][(cis^25) (-2x)]}/{[(cis^27)(x/3)][(cis^44) (-x/2)]]} = {[cis(36x)][cis(-50x)]} / {[cis(9x)][cis(-22x)]} = [cis(-14x)] / [cis(-13x)] = cis(-x) = cosx - i sinx
其他解答:
數學 complex number
發問:
simplify {[(cis^12)(3x)][(cis^25) (-2x)]}/{[(cis^27)(x/3)][(cis^44) (-x/2)]]}
最佳解答:
{[(cis^12)(3x)][(cis^25) (-2x)]}/{[(cis^27)(x/3)][(cis^44) (-x/2)]]} = {[cis(36x)][cis(-50x)]} / {[cis(9x)][cis(-22x)]} = [cis(-14x)] / [cis(-13x)] = cis(-x) = cosx - i sinx
其他解答:
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