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6.The mass of six concrete blocks were measured before used in construction site as below:No.123456Mass (kg)20.020.520.020.520.021.0a)Calculate the mean, mode, median and standard deviation of the measured set of masses;b)If two blocks are picked up to use at random, one after the other and without... 顯示更多 6.The mass of six concrete blocks were measured before used in construction site as below: No.123456 Mass (kg)20.020.520.020.520.021.0 a)Calculate the mean, mode, median and standard deviation of the measured set of masses; b)If two blocks are picked up to use at random, one after the other and without replacement, find the probability that: i) the two blocks picked up are of the same value; ii) one of the blocks picked up is a 20.0 kg and the other is a 20.5kg; and iii) none of the blocks picked up is a 20.0 kg.
最佳解答:
Are their masses in kg, 20.0, 20.5, 20.0, 20.5, 20.0 and 21.0? if yes, then, Let's rearrage them in accending order as follow: 20,20,20,20.5,20.5,21 a) Mean= Sum / 6 = 122/6=61/3 Mode= 20.0 Media = (20.0+20.5 )/2 =20.25 SD= {(1/6)*[(61/3-20)^2*3+(61/3-20.5)^2*2+(61/3-21)^2]}^(1/2) =0.372(cor. to 3 sig.fig.) b)i) 3/6*2/5+2/6*1/5=4/15 ii) 3/6*2/5+2/6*3/5=2/5 iii) 3/6*2/5 =1/5
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mathematical and trigonometrical functions發問:
6.The mass of six concrete blocks were measured before used in construction site as below:No.123456Mass (kg)20.020.520.020.520.021.0a)Calculate the mean, mode, median and standard deviation of the measured set of masses;b)If two blocks are picked up to use at random, one after the other and without... 顯示更多 6.The mass of six concrete blocks were measured before used in construction site as below: No.123456 Mass (kg)20.020.520.020.520.021.0 a)Calculate the mean, mode, median and standard deviation of the measured set of masses; b)If two blocks are picked up to use at random, one after the other and without replacement, find the probability that: i) the two blocks picked up are of the same value; ii) one of the blocks picked up is a 20.0 kg and the other is a 20.5kg; and iii) none of the blocks picked up is a 20.0 kg.
最佳解答:
Are their masses in kg, 20.0, 20.5, 20.0, 20.5, 20.0 and 21.0? if yes, then, Let's rearrage them in accending order as follow: 20,20,20,20.5,20.5,21 a) Mean= Sum / 6 = 122/6=61/3 Mode= 20.0 Media = (20.0+20.5 )/2 =20.25 SD= {(1/6)*[(61/3-20)^2*3+(61/3-20.5)^2*2+(61/3-21)^2]}^(1/2) =0.372(cor. to 3 sig.fig.) b)i) 3/6*2/5+2/6*1/5=4/15 ii) 3/6*2/5+2/6*3/5=2/5 iii) 3/6*2/5 =1/5
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