標題:
坡度與斜面數學題2(15分)
細閱下圖,請以英文回答問題,題目可能涉及tan,sin,cos的應用 回答第3題 圖:http://img265.imagevenue.com/img.php?image=74992_9019670001_122_58lo.JPG 更新: 更正:是回答第5題
最佳解答:
Actually, the key point of this question is to find out the difference of the height of building B and that of building A, let the difference be "z" metres First, find out the height of building B: let the height of building B be "y" metres y/35 = tan 58 y = tan 58 x 35 So the difference z = 70 - y z = 70 - tan 58 x 35 Finally, extend the vertical line of building B upwards and draw a horizontal line from building A to building B to form a triangle, you should then realize: (assumed the angle that you have to find as "O") z/ 35 = tan O (70 - tan 58 x 35)/ 35 = tan O I think you would be able to find O then.
其他解答:
坡度與斜面數學題2(15分)
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發問:細閱下圖,請以英文回答問題,題目可能涉及tan,sin,cos的應用 回答第3題 圖:http://img265.imagevenue.com/img.php?image=74992_9019670001_122_58lo.JPG 更新: 更正:是回答第5題
最佳解答:
Actually, the key point of this question is to find out the difference of the height of building B and that of building A, let the difference be "z" metres First, find out the height of building B: let the height of building B be "y" metres y/35 = tan 58 y = tan 58 x 35 So the difference z = 70 - y z = 70 - tan 58 x 35 Finally, extend the vertical line of building B upwards and draw a horizontal line from building A to building B to form a triangle, you should then realize: (assumed the angle that you have to find as "O") z/ 35 = tan O (70 - tan 58 x 35)/ 35 = tan O I think you would be able to find O then.
其他解答:
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