標題:
Maths 2條
發問:
1) If f(x)=x^2 + 3x +1, find f(x+h)-f(x) / h 2)solve the equations: x^4 - 3x^2 + 1 = 0 (put y=x^2 and correct your ans to 2 decimal places) THX
最佳解答:
其他解答:
Maths 2條
發問:
1) If f(x)=x^2 + 3x +1, find f(x+h)-f(x) / h 2)solve the equations: x^4 - 3x^2 + 1 = 0 (put y=x^2 and correct your ans to 2 decimal places) THX
最佳解答:
此文章來自奇摩知識+如有不便請留言告知
1) (f(x+h)-f(x)) / h =(x2+2xh+h2+3x+3h+1-x2-3x-1) / h =(2xh+h2+3h) / h =2x+h+3 2) If y=x2, y2-3y+1=0 y=(3+sr5) / 2 y=2.62, 0.38 Therefore, x=1.62, 0.62其他解答:
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