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標題:
發問:
A girl's age is 2 years more than 1/2 of her mother's age. If the sum of their ages is 62, find their ages. *Use an basic algebra to answer the question*
最佳解答:
Let x be the mother's age Let y be the girl's age 1. y=x/2 + 2 2. x+y=62 Put 1 into 2 x+x/2+2=62 2x+x+4=124 3x=120 x=40 Put x=40 into 2 y=62-40 y=22
其他解答:
let the girl's age be x , and mother's age be y. x-2 = 1/2 y -------- (1) x + y = 62 --------- (2) from (2) x + y = 62 x = 62 - y ------- (3) sub (3) into (1), x-2 = 1/2 y (62-y) - 2 = 1/2 y 62-y-2 = 1/2 y 60 = 3/2 y y = 40 put y = 40 into (2) x + y = 62 x+40 = 62 x = 22 so the girl's age is 22 years old and her mother's age is 40 years old.|||||let age of girl be x age of mother be y x+y = 62 ---(1) x-2 = y/2 ---(2) (1)-(2), y+2 = 62 - y/2 2y + 4 = 124 - y y=40 x=22|||||girl's age = x, mother's age = y x = y/2 + 2, 2x = y + 4 ------------ (1) x + y = 62 ------------ (2) (1) + (2), 3x + y = y + 66, x = 22 22 + y = 62, y = 40 girl's age = 22, mother's age = 40
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Mathematical Question發問:
A girl's age is 2 years more than 1/2 of her mother's age. If the sum of their ages is 62, find their ages. *Use an basic algebra to answer the question*
最佳解答:
Let x be the mother's age Let y be the girl's age 1. y=x/2 + 2 2. x+y=62 Put 1 into 2 x+x/2+2=62 2x+x+4=124 3x=120 x=40 Put x=40 into 2 y=62-40 y=22
其他解答:
let the girl's age be x , and mother's age be y. x-2 = 1/2 y -------- (1) x + y = 62 --------- (2) from (2) x + y = 62 x = 62 - y ------- (3) sub (3) into (1), x-2 = 1/2 y (62-y) - 2 = 1/2 y 62-y-2 = 1/2 y 60 = 3/2 y y = 40 put y = 40 into (2) x + y = 62 x+40 = 62 x = 22 so the girl's age is 22 years old and her mother's age is 40 years old.|||||let age of girl be x age of mother be y x+y = 62 ---(1) x-2 = y/2 ---(2) (1)-(2), y+2 = 62 - y/2 2y + 4 = 124 - y y=40 x=22|||||girl's age = x, mother's age = y x = y/2 + 2, 2x = y + 4 ------------ (1) x + y = 62 ------------ (2) (1) + (2), 3x + y = y + 66, x = 22 22 + y = 62, y = 40 girl's age = 22, mother's age = 40
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