標題:
force
發問:
Two blocks A and B of mass M and m respectively are placed in contact ona smooth horizontal table and a horizontal force F acts on block m as shown http://img15.imgspot.com/?u=/u/07/52/08/f1172152069.JPG Find the magnitude of force acting on block A by block B
最佳解答:
F=ma in this case, F=(m+M)a while force acting on block A by block B, f=Ma a=F/(M+m) so f=FM/(M+m) so the magnitude of force force acting on block A by block B is FM/(M+m) 2007-02-22 23:18:52 補充： just discover a mistake by remaining of garychiu_2003f should be the force acting on block B by block Aforce acting on block A by block B is 0 since there is a smooth table, no force can give the reaction force to B to make a reaction force on block A. 2007-02-22 23:18:59 補充： so the force acting on block B by block A is FM/(M m).the force acting on block A by block B is 0 2007-02-26 21:57:17 補充： net force of A=ma=F-the force acting on block A by block Bthe force acting on block A by block B=F-ma=(m加M)a-ma=Ma=FM/(M加m)so the force acting on block A by block B is also FM/(M加m)
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