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(1+x)^q-(1-x)^q-(2x)^q=0
發問:
(1+x)^q-(1-x)^q-(2x)^q=0 q>1 is a constant, solve for x.
最佳解答:
========================================================= 圖片參考：http://img175.imageshack.us/img175/5598/28703174.png 2010-04-26 21:58:42 補充： http://img175.imageshack.us/img175/5598/28703174.png
其他解答:
why x=1 is the only solution? 2010-04-27 01:00:49 補充： What it q is not an integer?|||||put x=1, (1+1)^q-(1-1)^q-(2*1)^q=2^q-0^q-2^q=0
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