標題:
有無人識得做呢題Physics Question (Mechanics)？
發問:
更新: 有無人識得做呢題Physics Question (Mechanics)，Part B?
最佳解答:
Parabola: y(t) = pt^2 + qt + r y(2) = 4p + 2q + r = 0.75 ..... (1) y(3.3) = 10.89p + 3.3q + r = 1.2 ..... (2) y(4.5) = 20.25p + 4.5q + r = 0.9 ..... (3) Eq.(2) - Eq.(1): 6.89p + 1.3q = 0.45 ..... (4) Eq.(3) - Eq.(2): 9.36p + 1.2q = -0.3 ..... (5) Both Eqs.(4) & (5): p = -0.23846, q = 1.61 Eq.(1): r = 0.75 + 4*0.23846 - 2*1.61 = -1.516 y(t) = -0.23846t^2 + 1.61t - 1.516 meter v(t) = y'(t) = -0.47692t + 1.61 m/s a(t) = y"(t) = -0.47692 m/s^2
其他解答:
有無人識得做呢題Physics Question (Mechanics)？
發問:
更新: 有無人識得做呢題Physics Question (Mechanics)，Part B?
最佳解答:
Parabola: y(t) = pt^2 + qt + r y(2) = 4p + 2q + r = 0.75 ..... (1) y(3.3) = 10.89p + 3.3q + r = 1.2 ..... (2) y(4.5) = 20.25p + 4.5q + r = 0.9 ..... (3) Eq.(2) - Eq.(1): 6.89p + 1.3q = 0.45 ..... (4) Eq.(3) - Eq.(2): 9.36p + 1.2q = -0.3 ..... (5) Both Eqs.(4) & (5): p = -0.23846, q = 1.61 Eq.(1): r = 0.75 + 4*0.23846 - 2*1.61 = -1.516 y(t) = -0.23846t^2 + 1.61t - 1.516 meter v(t) = y'(t) = -0.47692t + 1.61 m/s a(t) = y"(t) = -0.47692 m/s^2
其他解答:
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