標題:

升中一暑期作業問題(方程式) (((急)))

發問:

升中一數學題(方程式) (((急))) 要列式 (a) 5x + 3 = 48 (b) 12x - 8 = 16 (c) 4x + 6 = 30 (d) 6 ( x + 2 ) = 12 (e) 6分之1 ( 27 - 3x ) = 6 (f) 14分之3 ( 2x + 7 ) = 1 (g) 7分之2 ( 3x + 7 ) + 1 = 9 (h) 9分之5 ( x + 2 ) = 18分之3 ( 3x + 8 ) 唔該晒!!!超急t_t希望各位幫幫手

最佳解答:

(a) 5x + 3 = 48 5x = 45 x = 15 (b) 12x - 8 = 16 12x = 24 x = 2 (c) 4x + 6 = 30 4x = 24 x = 6 (d) 6 ( x + 2 ) = 12 x + 2 = 2 x = 0 (e) 1/6 ( 27 - 3x ) = 6 27-3x = 36 -9 = 3x x = -3 (f) 3/14*( 2x + 7 ) = 1 3(2x+7) = 14 6x + 21 = 14 6x = -7 x = -7/6 (g) 2/7*( 3x + 7 ) + 1 = 9 7[2/7*(3x+7) + 1] = 7(9) 2(3x+7) + 7 = 63 2(3x+7) = 56 3x+7 = 28 3x = 21 x = 7 (h) 5/9 * ( x + 2 ) = 3/18 * ( 3x + 8 ) 18[5/9 * (x+2)] = 18[3/18 * (3x+8)] 10(x+2) = 3(3x+8) 10x + 20 = 9x + 24 x = -4

其他解答:

(a) 5x + 3 = 48 5x=48-3 5x=45 x=45/5 x=9 (b) 12x - 8 = 16 12x=16+8 12x=24 x=24/12 x=2 (c) 4x + 6 = 30 4x=30-6 4x=24 x=24/4 x=6 (d) 6 ( x + 2 ) = 12 x+2=12/6 x+2=2 x=2-2 x-0 (e) 6分之1 ( 27 - 3x ) = 6 27 - 3x =6/6分之1 27 - 3x =36 -3x=36-27 -3x=9 x=9+3 x=11 (f) 14分之3 ( 2x + 7 ) = 1 3(2x+7) = 14 6x + 21 = 14 6x = 14-21 6x = -7 x = -7/6 (g) 7分之2 ( 3x + 7 ) + 1 = 9 2(3x+7) + 1 = 7(9) 2(3x+7) + 1 = 63 2(3x+7) = 63-1 2(3x+7) =62 3x+7 =62/2 3x+7 = 31 3x=31-7 3x = 24 x =24/3 x =8 (h) 9分之5 ( x + 2 ) = 18分之3 ( 3x + 8 ) 18[9分之5 (x+2)] = 18[18分之3 (3x+8)] 10(x+2) = 3(3x+8) 10x + 20 = 9x + 24 10x-9x = 24-20 x = 4

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