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物理問題一問(波動) [光波]
發問:
波長590nm的黃光法向入射於一塊每亳米刻有400線的衍射光珊。求第三級和第四級亮紋角位置的差別。 A. 13.7° B. 25.7° C. 45.1° D. 70.7° 詳細解釋，唔該。
Use formula: a.sin(p) = m入 where a is the grating line spacing angle p is the angular position of a bright fringe 入 is the wavelength of light used m is an interger. Here, a = 1/400 mm = 2.5 x 10^-3 mm = 2.5 x 10^-6 m 入= 590 x 10^-9 m = 5.9 x 10^-7 m For the 3rd order fringe, m = 3 Hence, (2.5x10^-6).sin(p) = 3 x 5.9x10^-7 sin(p) = 0.708 p = 45.07 degrees For the 4th order fringe, m = 4 Hence, (2.5x10^-6).sin(p) = 4 x 5.9x10^-7 sin(p) = 0.944 p = 70.73 degrees Therefore, separation of angular positions = (70.73 - 45.07) degrees = 25.66 degrees The answer is option B
其他解答:
物理問題一問(波動) [光波]
發問:
波長590nm的黃光法向入射於一塊每亳米刻有400線的衍射光珊。求第三級和第四級亮紋角位置的差別。 A. 13.7° B. 25.7° C. 45.1° D. 70.7° 詳細解釋，唔該。
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最佳解答:Use formula: a.sin(p) = m入 where a is the grating line spacing angle p is the angular position of a bright fringe 入 is the wavelength of light used m is an interger. Here, a = 1/400 mm = 2.5 x 10^-3 mm = 2.5 x 10^-6 m 入= 590 x 10^-9 m = 5.9 x 10^-7 m For the 3rd order fringe, m = 3 Hence, (2.5x10^-6).sin(p) = 3 x 5.9x10^-7 sin(p) = 0.708 p = 45.07 degrees For the 4th order fringe, m = 4 Hence, (2.5x10^-6).sin(p) = 4 x 5.9x10^-7 sin(p) = 0.944 p = 70.73 degrees Therefore, separation of angular positions = (70.73 - 45.07) degrees = 25.66 degrees The answer is option B
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