標題:
Help me for my work please
發問:
Please help that New Trend Mathematics P.4.21-Q15 answer! and a formula!! Thankyou 更新: Carl has $9 more then David does. Hilbert has 3分之1 of the amount of Carl.If they have a total amount of $61, how much does each of them have?
最佳解答:
Let David has $x, Carl has $(x+9), and Hilbert has (x+9)/3. x+(x+9)+(x+9)/3=61 2x+(x+9)/3=52 6x+x+9=156 7x=147 x=21 Thus, David has $21 Carl has $(21+9), ie, $30 Hilbert has (21+9)/3, ie. $10 2013-10-28 20:13:32 補充： 其實設2個未知數、3個未知數都得； 不過設得愈少未知數，就愈簡單，也計得愈快。
其他解答:
Help me for my work please
發問:
Please help that New Trend Mathematics P.4.21-Q15 answer! and a formula!! Thankyou 更新: Carl has $9 more then David does. Hilbert has 3分之1 of the amount of Carl.If they have a total amount of $61, how much does each of them have?
最佳解答:
Let David has $x, Carl has $(x+9), and Hilbert has (x+9)/3. x+(x+9)+(x+9)/3=61 2x+(x+9)/3=52 6x+x+9=156 7x=147 x=21 Thus, David has $21 Carl has $(21+9), ie, $30 Hilbert has (21+9)/3, ie. $10 2013-10-28 20:13:32 補充： 其實設2個未知數、3個未知數都得； 不過設得愈少未知數，就愈簡單，也計得愈快。
其他解答:
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