標題:

畢氏定理問題x 1

發問:

AC^2 + (4/3AC)^2 = 7.5^2 <計AC 點計? 請比step. thanks 答案must be 4.5 更新: AC^2 + (4/3AC)^2 = 7.5^2 計AC

最佳解答:

AC^2 + (4/3AC)^2 = 7.5^2 AC^2 + (4/3AC)^2 = 56.25 AC^2 + (16/9)AC^2 = 56.25 25.9AC^2 = 56.25 AC^2 = 20.25 AC = 4.5 2009-12-10 21:33:19 補充： AC^2 + (4/3AC)^2 = 7.5^2 AC^2 + (4/3AC)^2 = 56.25 AC^2 + (16/9)AC^2 = 56.25 25/9AC^2 = 56.25 AC^2 = 20.25 AC = 4.5 上面的錯了,這樣才對 2009-12-10 21:34:46 補充： AC^2 + (4/3AC)^2 = 7.5^2 AC^2 + (4/3AC)^2 = 56.25 AC^2 + (16/9)AC^2 = 56.25 (25/9)AC^2 = 56.25 AC^2 = 20.25 AC = 4.5 真正好了.用這個

其他解答:

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此文章來自奇摩知識+如有不便請留言告知

最簡單方法 AC^2 + (4/3AC)^2 = 7.5^2 AC^2+ (4/3)^2xAC^2=7.5^2 抽個ac^2出來 AC^2x(1+(4/3)^2)=7.5^2 AC=開方(7.5^2)/(1+(4/3)^2) =4.5 2009-12-11 14:11:06 補充： 你個答案好似錯wor,應該係正負4.5 2009-12-11 14:13:22 補充： AC^2=(7.5^2)/(1+(4/3)^2) 因為ac^2等於一舊正數，咁ac=-4.5,ac^2都係等於一舊正數
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