標題:
engin science 3
An 1 horsepower (1HP = 745.7W) air-conditioner operates 12 hours per day.Assuming that the compressor of the air-conditioner turns on for 85% of the time and for the remaining time, the air-conditioner just uses 40W.a) Calculate the energy consumed (kWh) within two months (61 days).b) If the tariff is... 顯示更多 An 1 horsepower (1HP = 745.7W) air-conditioner operates 12 hours per day. Assuming that the compressor of the air-conditioner turns on for 85% of the time and for the remaining time, the air-conditioner just uses 40W. a) Calculate the energy consumed (kWh) within two months (61 days). b) If the tariff is $1.322 per kWh (CLP), calculate the bi-monthly bill for using the air-conditioner.
最佳解答:
(a) In one day, the enrgy consumed by the air-conditioner = (745.7 x 0.85 + 40 x 0.15 ) x 12 x 3600 J = 2.764 x 10^7 J = 2.764 x 10^4 kJ In 61 days, energy consumed = 2.764 x 10^4 x 61 kJ = 1.686 x 10^6 kJ Since 1 kw-h = 3600 kJ hence, Energy consumed in 61 days = 1.686 x 10^6/3600 kw-h = 468.3 kw-h (b) Amount of expenses = $468.3 x 1.322 = $619
其他解答:
engin science 3
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發問:An 1 horsepower (1HP = 745.7W) air-conditioner operates 12 hours per day.Assuming that the compressor of the air-conditioner turns on for 85% of the time and for the remaining time, the air-conditioner just uses 40W.a) Calculate the energy consumed (kWh) within two months (61 days).b) If the tariff is... 顯示更多 An 1 horsepower (1HP = 745.7W) air-conditioner operates 12 hours per day. Assuming that the compressor of the air-conditioner turns on for 85% of the time and for the remaining time, the air-conditioner just uses 40W. a) Calculate the energy consumed (kWh) within two months (61 days). b) If the tariff is $1.322 per kWh (CLP), calculate the bi-monthly bill for using the air-conditioner.
最佳解答:
(a) In one day, the enrgy consumed by the air-conditioner = (745.7 x 0.85 + 40 x 0.15 ) x 12 x 3600 J = 2.764 x 10^7 J = 2.764 x 10^4 kJ In 61 days, energy consumed = 2.764 x 10^4 x 61 kJ = 1.686 x 10^6 kJ Since 1 kw-h = 3600 kJ hence, Energy consumed in 61 days = 1.686 x 10^6/3600 kw-h = 468.3 kw-h (b) Amount of expenses = $468.3 x 1.322 = $619
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