標題:
PHYSICS electrostatics
發問:
最佳解答:
For uniform electric field,By E = V/d V is the potential difference between the two plates d is the separation of the two plates E is the electric field between the two plates Now, because Q = CV, where C is the capacitance of the two plates We have C = Q / V Now, C = ε0A / d Combing the equations, we have E = Q / ε0A where Q is the charge on the plates A is the overlapping area of the plates ε0 is the permittivity of vacuum So, 55 = Q / (8.85 X 10-12)(1.0) Charge on the plates, Q = 4.87 X 10-10 C
其他解答:
by Guass Law, (let E be electric field due to one plate only) construct a small surface on a plate 2EA= Q/eo As the two plate are in opposite charge the field inside is 2E hence total charge of one plate Q = 2EAeo= 55 * 1 * permittivity Note that , the bothe calculation has an assumption that the field lines between plates is prependacular to each plate , so the field strength is indenpendent of the distance ( by guass law)
PHYSICS electrostatics
發問:
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two large metal plates of area 1.0m^2 face each other. They are separated by 5.0cm and carrying equal and opposite charges. If the electric field between the plates is 55 N/C, what is the charge on the plates? (Edge effect is neglected.)最佳解答:
For uniform electric field,By E = V/d V is the potential difference between the two plates d is the separation of the two plates E is the electric field between the two plates Now, because Q = CV, where C is the capacitance of the two plates We have C = Q / V Now, C = ε0A / d Combing the equations, we have E = Q / ε0A where Q is the charge on the plates A is the overlapping area of the plates ε0 is the permittivity of vacuum So, 55 = Q / (8.85 X 10-12)(1.0) Charge on the plates, Q = 4.87 X 10-10 C
其他解答:
by Guass Law, (let E be electric field due to one plate only) construct a small surface on a plate 2EA= Q/eo As the two plate are in opposite charge the field inside is 2E hence total charge of one plate Q = 2EAeo= 55 * 1 * permittivity Note that , the bothe calculation has an assumption that the field lines between plates is prependacular to each plate , so the field strength is indenpendent of the distance ( by guass law)
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