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標題:
MATHS: interest
發問:
Mary has found her dream house. It is selling for $500000. When she retires 2 years from now, she plans to sell her present house for $450000 an move. She decides to set aside $900 every two weeks until she retires in a fund earning 10.5%/a, compounded every second week. What is the difference between the future... 顯示更多 Mary has found her dream house. It is selling for $500000. When she retires 2 years from now, she plans to sell her present house for $450000 an move. She decides to set aside $900 every two weeks until she retires in a fund earning 10.5%/a, compounded every second week. What is the difference between the future value of Mary's investment extra $50000 she needs for her dream home? 更新: you are so great, super.
最佳解答:
先澄清兩點： (1) 是否 10.5% p.a. (2) 你是否假設一年有 52 個星期？ 〔這個不同的假設會影響計算，因為若是的話，那 two-month compounded rate is 10.5%/26〕 2015-06-18 11:27:38 補充： For each year, assume that there are 52 weeks. Then for two years, there are 104 weeks, that is, 52 two-weeks period. Consider a time line (vertical illustrated below) with each time unit being 2 weeks. ０＋ ｜ １＋＜－－＄９００ ｜ ２＋＜－－＄９００ ｜ ３＋＜－－＄９００ ｜ ．．． ｜ ５１＋＜－－＄９００ ｜ ５２＋＜－－＄９００ ｜ ｖ For every two weeks, the interest rate is i = 10.5%/26. The amount of money Mary can accumulated is $900(1 + i)?1 + $900(1 + i)?? + ... + $900(1 + i)2 + $900(1 + i) + $900 = $900 + $900(1 + i) + $900(1 + i)2 + ... + $900(1 + i)?? + $900(1 + i)?1 = $900[(1 + i)?2 - 1] / [(1 + i) - 1] = $900[(1 + i)?2 - 1] / i = $51960.57972 The difference is $51960.57972 - ($500000 - $450000) = $51960.57972 - $50000 = $1960.57972
其他解答:
MATHS: interest
發問:
Mary has found her dream house. It is selling for $500000. When she retires 2 years from now, she plans to sell her present house for $450000 an move. She decides to set aside $900 every two weeks until she retires in a fund earning 10.5%/a, compounded every second week. What is the difference between the future... 顯示更多 Mary has found her dream house. It is selling for $500000. When she retires 2 years from now, she plans to sell her present house for $450000 an move. She decides to set aside $900 every two weeks until she retires in a fund earning 10.5%/a, compounded every second week. What is the difference between the future value of Mary's investment extra $50000 she needs for her dream home? 更新: you are so great, super.
最佳解答:
先澄清兩點： (1) 是否 10.5% p.a. (2) 你是否假設一年有 52 個星期？ 〔這個不同的假設會影響計算，因為若是的話，那 two-month compounded rate is 10.5%/26〕 2015-06-18 11:27:38 補充： For each year, assume that there are 52 weeks. Then for two years, there are 104 weeks, that is, 52 two-weeks period. Consider a time line (vertical illustrated below) with each time unit being 2 weeks. ０＋ ｜ １＋＜－－＄９００ ｜ ２＋＜－－＄９００ ｜ ３＋＜－－＄９００ ｜ ．．． ｜ ５１＋＜－－＄９００ ｜ ５２＋＜－－＄９００ ｜ ｖ For every two weeks, the interest rate is i = 10.5%/26. The amount of money Mary can accumulated is $900(1 + i)?1 + $900(1 + i)?? + ... + $900(1 + i)2 + $900(1 + i) + $900 = $900 + $900(1 + i) + $900(1 + i)2 + ... + $900(1 + i)?? + $900(1 + i)?1 = $900[(1 + i)?2 - 1] / [(1 + i) - 1] = $900[(1 + i)?2 - 1] / i = $51960.57972 The difference is $51960.57972 - ($500000 - $450000) = $51960.57972 - $50000 = $1960.57972
其他解答:
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我也是這樣想,假設一年有 52 個星期.. The answer is $51960.58 and $1960.58
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