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標題:
maths~``
發問:
As follows: 圖片參考：http://i.imagehost.org/0761/ScreenHunter_03_Nov_13_20_46.gif
最佳解答:
ㄥACD = ㄥDCB - ㄥACB = (180 - 64*2) - (180 - 128)/2 = 52 - 26 = 26度
其他解答:
Since BA = AC, therefore angle CBA = angle BCA = (180-128)/2 = 26 degree. But DC = BC, so that angle CDB = angle CBD = 64 degree, and angle DCB = 180 - 64 - 64 = 52 degree Hence angle ACD = 52 - 26 = 26 degree.
maths~``
發問:
As follows: 圖片參考：http://i.imagehost.org/0761/ScreenHunter_03_Nov_13_20_46.gif
最佳解答:
ㄥACD = ㄥDCB - ㄥACB = (180 - 64*2) - (180 - 128)/2 = 52 - 26 = 26度
其他解答:
Since BA = AC, therefore angle CBA = angle BCA = (180-128)/2 = 26 degree. But DC = BC, so that angle CDB = angle CBD = 64 degree, and angle DCB = 180 - 64 - 64 = 52 degree Hence angle ACD = 52 - 26 = 26 degree.
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