標題:
Limiting Reactant
發問:
In the blast furnace, the overall reaction is 2Fe2O3 (s) + 3C (s) -------> 3CO2 (g) + 4Fe (s) what is the maximum mass of iron that can be obtained from 700 tonnes of iron (III) oxide and 70 tonnes of coke? [1 tonne = 1000 kg] 更新: Given the relative atomic mass of Fe = 55.8 ; O = 16.0 ; C = 12.0 更新 2: Some calculation errors you make: No. of moles of Fe2O-3 added = (700 x 1000 x 1000)/159.6 = 4.403 x 10^6 mol It should be 4.386x10^6 mol But nevermind~ 更新 3: Cheers!
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最佳解答:
The maximum mass of Fe can be obtained when coke contains 100% of carbon and the reaction is complete. 2Fe2O3 + 3C → 3CO2 + 4Fe In the reaction, mole ratio Fe2O3 : C = 2 : 3 Molar mass of Fe2O3 = 55.8x2 + 16x3 = 159.6 g/mol Molar mass of C = 12 g/mol No. of moles of Fe2O-3 added = (700 x 1000 x 1000)/159.6 = 4.403 x 10^6 mol No. of moles of C added = (70 x 1000 x 1000)/12 = 5.833 x 10^6 mol If C is completely reacted, Fe2O3 needed = (5.833 x 10^6) x (2/3) = 3.889 x 10^6 mol Hence, Fe2O3 is in excess, and C is the limiting reactant (completely reacted). Mole ratio C : Fe = 3 : 4 No. of moles of C reacted = 5.833 x 10^6 mol No. of moles of Fe formed = (5.833 x 10^6) x (4/3) = 7.777 x 10^6 mol Maximum mass of Fe formed = (7.777 x 10^6) x 55.8 = 4.34 x 10^8 g = 434 tonnes 2009-11-25 23:04:50 補充： Yes, it should be 4.386x10^6 mol, but not 4.403 x 10^6 mol. However, this step would not affect all the other steps of the answer.
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