標題:
Math一問~~~~~~~~
發問:
A ship sails 60 km in the direction of ENE and then 80km in the direction of SSE . Find the true bearing of the final position of the ship from the starting point .
最佳解答:
A ship sails 60 km in the direction of ENE and then 80km in the direction of SSE . Find the true bearing of the final position of the ship from the starting point 如圖所示 圖片參考：http://hk.geocities.com/namsm4e/p0117.jpg 船由A點向ENE行了60km 到達 B 點，再向 SSE 行了 80km 到達 C 點 圖中∠ABC = 90o，所以最後的位移 AC 可用畢氏定理計算。 AC = √(AB2 + BC2) = √(602 + 802) = 100km 及 ∠BAC = tan-1(80/60) = 53.1o 53.1 – 22.5 = 30.6o 所以方位為 E30.6oS 結果為 100km E30.6oS
Math一問~~~~~~~~
發問:
A ship sails 60 km in the direction of ENE and then 80km in the direction of SSE . Find the true bearing of the final position of the ship from the starting point .
最佳解答:
A ship sails 60 km in the direction of ENE and then 80km in the direction of SSE . Find the true bearing of the final position of the ship from the starting point 如圖所示 圖片參考：http://hk.geocities.com/namsm4e/p0117.jpg 船由A點向ENE行了60km 到達 B 點，再向 SSE 行了 80km 到達 C 點 圖中∠ABC = 90o，所以最後的位移 AC 可用畢氏定理計算。 AC = √(AB2 + BC2) = √(602 + 802) = 100km 及 ∠BAC = tan-1(80/60) = 53.1o 53.1 – 22.5 = 30.6o 所以方位為 E30.6oS 結果為 100km E30.6oS
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