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Gas Stoichiometry 問題求教
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5.What volume of N2 (g) and that of O2 (g) would yield 2.5 L of N2O5 (g) in the following reaction?2N2(g) + 5O2 (g) ----------> 2 N2O5 (g)6.What volume of I2 (g) would be needed to react with 1.35 L of H2 (g) in the following reaction? How many liters of HI would be formed?I2(g) + H2 (g) ... 顯示更多 5.What volume of N2 (g) and that of O2 (g) would yield 2.5 L of N2O5 (g) in the following reaction? 2N2(g) + 5O2 (g) ----------> 2 N2O5 (g) 6.What volume of I2 (g) would be needed to react with 1.35 L of H2 (g) in the following reaction? How many liters of HI would be formed? I2(g) + H2 (g) ----------> 2 HI (g)(? L) 7. If 2.38 L of SO3 gas, measured at 65.0 ?C and 1.05 atm, is passed through liquid water, how many moles of the product sulfuric acid are formed? How many grams? The balanced equation is: SO3(g) + H2O (l) ---------> H2SO4(l)
Avogadro's law states that, "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules. 5.What volume of N2 (g) and that of O2 (g) would yield 2.5 L of N2O5 (g) in the following reaction? 2N2(g) + 5O2 (g) ----------> 2 N2O5 (g) Vol. of N? = (2.5 )(2/2) = 2.5 L Vol. of O? = (2.5)(5/2) = 6.25 L 6.What volume of I2 (g) would be needed to react with 1.35 L of H2 (g) in the following reaction? How many liters of HI would be formed? I2(g) + H2 (g) ----------> 2 HI (g)(? L) Vol. of I? = (1.35)(1/1) = 1.35 L Vol. of HI = (1.35)(2/1) = 2.7 L 7. If 2.38 L of SO3 gas, measured at 65.0 ?C and 1.05 atm, is passed through liquid water, how many moles of the product sulfuric acid are formed? How many grams? The balanced equation is: SO3(g) + H2O (l) ---------> H2SO4(l) PV = nRT (1.05)(2.38) = n(0.08206)(273+65) n = 0.0901 mole No. of mole of sulfuric acid formed = 0.0901 mole mass = (0.0901)(1X2+32+16X4) = 8.83 g
其他解答:
Gas Stoichiometry 問題求教
發問:
5.What volume of N2 (g) and that of O2 (g) would yield 2.5 L of N2O5 (g) in the following reaction?2N2(g) + 5O2 (g) ----------> 2 N2O5 (g)6.What volume of I2 (g) would be needed to react with 1.35 L of H2 (g) in the following reaction? How many liters of HI would be formed?I2(g) + H2 (g) ... 顯示更多 5.What volume of N2 (g) and that of O2 (g) would yield 2.5 L of N2O5 (g) in the following reaction? 2N2(g) + 5O2 (g) ----------> 2 N2O5 (g) 6.What volume of I2 (g) would be needed to react with 1.35 L of H2 (g) in the following reaction? How many liters of HI would be formed? I2(g) + H2 (g) ----------> 2 HI (g)(? L) 7. If 2.38 L of SO3 gas, measured at 65.0 ?C and 1.05 atm, is passed through liquid water, how many moles of the product sulfuric acid are formed? How many grams? The balanced equation is: SO3(g) + H2O (l) ---------> H2SO4(l)
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最佳解答:Avogadro's law states that, "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules. 5.What volume of N2 (g) and that of O2 (g) would yield 2.5 L of N2O5 (g) in the following reaction? 2N2(g) + 5O2 (g) ----------> 2 N2O5 (g) Vol. of N? = (2.5 )(2/2) = 2.5 L Vol. of O? = (2.5)(5/2) = 6.25 L 6.What volume of I2 (g) would be needed to react with 1.35 L of H2 (g) in the following reaction? How many liters of HI would be formed? I2(g) + H2 (g) ----------> 2 HI (g)(? L) Vol. of I? = (1.35)(1/1) = 1.35 L Vol. of HI = (1.35)(2/1) = 2.7 L 7. If 2.38 L of SO3 gas, measured at 65.0 ?C and 1.05 atm, is passed through liquid water, how many moles of the product sulfuric acid are formed? How many grams? The balanced equation is: SO3(g) + H2O (l) ---------> H2SO4(l) PV = nRT (1.05)(2.38) = n(0.08206)(273+65) n = 0.0901 mole No. of mole of sulfuric acid formed = 0.0901 mole mass = (0.0901)(1X2+32+16X4) = 8.83 g
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