標題:
chemistry fastttttt
發問:
22.2g of a metallic chloride sample was mixed with silver nitrate solution. The precipitate of silver chloride, AgCl was filtered, washed and dried. 57.4g solid was obtained.(a)Why should the precipitate be washed and dried?(b)Calculate (i)the mass of chloride ions in the precipitate.(ii)the number of... 顯示更多 22.2g of a metallic chloride sample was mixed with silver nitrate solution. The precipitate of silver chloride, AgCl was filtered, washed and dried. 57.4g solid was obtained. (a)Why should the precipitate be washed and dried? (b)Calculate (i)the mass of chloride ions in the precipitate. (ii)the number of moles of chloride ions in the precipitate. (iii)the mass of chloride ions in the metallic chloride sample. (iv)the number of moles of chloride ions in the metallic chloride. (c)(i)Find the mole ratio of metal to chlorine in the sample if the relative atomic mass of the metal is 40. (ii)Write the empirical formula of the metallic chloride (Use M as the symbol of the metal)
最佳解答:
a) Wash away any impurities and dry off water. b) i) 57.4 X (35.5/(35.5+108)) = 14.2(g) ii) 14.2 / 35.5 = 0.4 mole iii) 0.4 X 35.5 = 14.2 (g) iv)0.4 mole c) i) Mass of metal = 22.2 - 14.2 = 8 No. of mole of metal = 8 / 40 = 0.2 mole Mole ratio = 0.2 : 0.4 =1:2 ii) MCl2 2013-09-24 14:04:23 補充： drive off water
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