標題:
Equation of circle
發問:
It is given that the equation of circle C1 is x^2+y^2+4x-2y-59=0, and the centre of circle C2 is (1,5). If C2 lies inside C1 and they touch each other internally, find the equation if C2
最佳解答:
It is given that theequation of circle C1 is x2 + y2 + 4x - 2y - 59 = 0, and the centre of circleC2 is (1, 5). If C2 lies inside C1 andthey touch each other internally, find the equation if C2. C1: x2 + y2 + 4x - 2y - 59 = 0 Centre of C1, O1= (-4/2, -(-2)/2) = (-2, 1) Radius of C1, r1= √[(4/2)2 + (-2/2)2 - (-59)] = 8 Centre of C2,O2= (1, 5) Radius of C2 = r2 C2 lies inside C1 and they touch each other internally: r1 = r2 + O1O2 8 = r2 + √[(1 + 3)2 + (5 - 1)2] 8 = r2 + 5 r2 = 3 Equation of C2 : (x - 1)2 + (y - 5)2 = 9 OR : x2 + y2 - 2x - 10y + 17 = 0
其他解答:
Equation of circle
發問:
It is given that the equation of circle C1 is x^2+y^2+4x-2y-59=0, and the centre of circle C2 is (1,5). If C2 lies inside C1 and they touch each other internally, find the equation if C2
最佳解答:
It is given that theequation of circle C1 is x2 + y2 + 4x - 2y - 59 = 0, and the centre of circleC2 is (1, 5). If C2 lies inside C1 andthey touch each other internally, find the equation if C2. C1: x2 + y2 + 4x - 2y - 59 = 0 Centre of C1, O1= (-4/2, -(-2)/2) = (-2, 1) Radius of C1, r1= √[(4/2)2 + (-2/2)2 - (-59)] = 8 Centre of C2,O2= (1, 5) Radius of C2 = r2 C2 lies inside C1 and they touch each other internally: r1 = r2 + O1O2 8 = r2 + √[(1 + 3)2 + (5 - 1)2] 8 = r2 + 5 r2 = 3 Equation of C2 : (x - 1)2 + (y - 5)2 = 9 OR : x2 + y2 - 2x - 10y + 17 = 0
其他解答:
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