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maths(more about probaility)
發問:
1.A card is picked at random from a pack of 52 playing-cards(without jokers).Find the probability of getting neither a diamond,a king nor a queen.2.There are balls in red ,yellow,blue,white and green in a bag.If a ball is drawn at random,the probailities of drawing balls in different colours are as... 顯示更多 1.A card is picked at random from a pack of 52 playing-cards(without jokers).Find the probability of getting neither a diamond,a king nor a queen. 2.There are balls in red ,yellow,blue,white and green in a bag.If a ball is drawn at random,the probailities of drawing balls in different colours are as follows. P(red)=1/6,P(yellow)=1/4, P(blue)=1/8,P(white)=3P(green) Find the probability of drawing a green ball.
最佳解答:
1.Since there are 13 diamond card, so the number of cards that are not diamond is 52-13=39 and there are 3 kings and 3 queens left in the remainning, so the numbers of cards that are not neither a diamond, a king nor a queen is 39-3-3=33 therefore the probability of getting neither a diamond, a king nor a queen is 33/52 2. Since adding all the probabilities is 1 therefore P(red)+P(yellow)+P(Blue)+P(white)+P(green)=1 subsitute P(white)=3P(green) into it, then we have P(red)+P(yellow)+P(Blue)+4P(green)=1 1/6+1/4+1/8+4P(green)=1 therefore, P(green)=1196 2007-11-10 21:53:06 補充： the ans is 11/96
maths(more about probaility)
發問:
1.A card is picked at random from a pack of 52 playing-cards(without jokers).Find the probability of getting neither a diamond,a king nor a queen.2.There are balls in red ,yellow,blue,white and green in a bag.If a ball is drawn at random,the probailities of drawing balls in different colours are as... 顯示更多 1.A card is picked at random from a pack of 52 playing-cards(without jokers).Find the probability of getting neither a diamond,a king nor a queen. 2.There are balls in red ,yellow,blue,white and green in a bag.If a ball is drawn at random,the probailities of drawing balls in different colours are as follows. P(red)=1/6,P(yellow)=1/4, P(blue)=1/8,P(white)=3P(green) Find the probability of drawing a green ball.
最佳解答:
1.Since there are 13 diamond card, so the number of cards that are not diamond is 52-13=39 and there are 3 kings and 3 queens left in the remainning, so the numbers of cards that are not neither a diamond, a king nor a queen is 39-3-3=33 therefore the probability of getting neither a diamond, a king nor a queen is 33/52 2. Since adding all the probabilities is 1 therefore P(red)+P(yellow)+P(Blue)+P(white)+P(green)=1 subsitute P(white)=3P(green) into it, then we have P(red)+P(yellow)+P(Blue)+4P(green)=1 1/6+1/4+1/8+4P(green)=1 therefore, P(green)=1196 2007-11-10 21:53:06 補充： the ans is 11/96
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