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標題:
find a horizontal force F
發問:
A box of mass m=37.6kg is pushed upward with an acceleration a=8.1ms^-2 by a horizontal force F. The slope on which the box rests makes an angle α=48 degree. What should be the force F? Refer to the figure below. The unit of the answer is N. http://upload.lsforum.net/users/public/w38060RWz238.png 更新: 個答案岩呀,thx 不過我重想知點解唔洗理個ukn(摩擦力) F.cos(48) - ukn - mg.sin(48) = ma
The force component that pushes the box going up the plane = F.cos(48) Hence, use : net force = mass x acceleration F.cos(48) - mg.sin(48) = ma i.e. F = [m(a + g.sin(48))]/cos(48) = [37.6 x (8.1 + 10.sin(48))]/cos(48) N F = 873 N [Take g, the acceleration due to gravity, to be 10 m/s^2]
其他解答:
find a horizontal force F
發問:
A box of mass m=37.6kg is pushed upward with an acceleration a=8.1ms^-2 by a horizontal force F. The slope on which the box rests makes an angle α=48 degree. What should be the force F? Refer to the figure below. The unit of the answer is N. http://upload.lsforum.net/users/public/w38060RWz238.png 更新: 個答案岩呀,thx 不過我重想知點解唔洗理個ukn(摩擦力) F.cos(48) - ukn - mg.sin(48) = ma
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最佳解答:The force component that pushes the box going up the plane = F.cos(48) Hence, use : net force = mass x acceleration F.cos(48) - mg.sin(48) = ma i.e. F = [m(a + g.sin(48))]/cos(48) = [37.6 x (8.1 + 10.sin(48))]/cos(48) N F = 873 N [Take g, the acceleration due to gravity, to be 10 m/s^2]
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