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Find the range of x if x is an integer. 122 > x2 > 63 x < (x+10)/2 歡迎詳寫！

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First consider x < ( x + 10 ) / 2 2x < x + 10 x < 10 Next consider 122 > x2 > 63. For x is an integer, the smallest value of x which can satisfy the condition is 8 since 82 = 64. The greatest value of x which can satisfy the condition is 11 since 112 = 121. From that, 7 < x < 12. Lastly, by combination, 7 < x < 10.

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