標題:
完全唔識的 probability 請指教 thx~
發問:
Q2 Bag X contains 5 black balls, 4 white balls and 3 green balls. Bag Y contains 4 black balls and 3 white balls. A ball is chosen at random from bag X and put into bag Y, and then a ball is drawn from bag Y. Find the probability that the second ball is in bag Y originally, given that it is black. Ans 48/53
最佳解答:
P(B)=5/12*5/8+7/12*4/8=25/96+28/96=53/96 P(YB)=5/12*4/8+7/12*4/8=20/96+28/96=48/96 P(Y|B) =P(YB)/P(B) =(48/96)/(53/96) =48/53 if you don"t understand, please ask me again
完全唔識的 probability 請指教 thx~
發問:
Q2 Bag X contains 5 black balls, 4 white balls and 3 green balls. Bag Y contains 4 black balls and 3 white balls. A ball is chosen at random from bag X and put into bag Y, and then a ball is drawn from bag Y. Find the probability that the second ball is in bag Y originally, given that it is black. Ans 48/53
最佳解答:
P(B)=5/12*5/8+7/12*4/8=25/96+28/96=53/96 P(YB)=5/12*4/8+7/12*4/8=20/96+28/96=48/96 P(Y|B) =P(YB)/P(B) =(48/96)/(53/96) =48/53 if you don"t understand, please ask me again
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