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the question is below: http://i197.photobucket.com/albums/aa173/jack021103/03.jpg thx~~~
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Mathematic Question...
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the question is below: http://i197.photobucket.com/albums/aa173/jack021103/03.jpg thx~~~
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a) Q'N=QN =x // QR=QN NR NR=QR-QN =16-x // b) Q'N^2=NR^2 Q'R^2 x^2=(16-x)^2 8^2 x^2=256-32x x^2 64 x=10 cm // c) QN=QR-NR =16-6=10 When PM=2 MN^2=(QN-PM)^2 16^2 MN^2=(10-2)^2 256 MN=17.889cm (3 sig. fig.) //其他解答:
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