標題:
數學問題,代數,急急急!快快快, help!!,please
發問:
(a*b)/a+b+c=2 a+b+c=21 c*c=a*b*1.5+1 a= b= c=
最佳解答:
此文章來自奇摩知識+如有不便請留言告知
1.(a*b)/a+b+c=2 2.a+b+c=21 3.c*c=a*b*1.5+1 ______________________________________________________ mix 2. into 1. ______________________________________________________ =(a*b)/21=2 ______________________________________________________ put(/21)into right side, turn(/21)to(*21) ______________________________________________________ =a*b=21*2 4.=a*b=42 ______________________________________________________ put 4.(a*b) into 3. (... ...=a*b*... ...) ______________________________________________________ =c*c=42*1.5+1 =c*c=63+1 =c*c=64 =c=64/c ______________________________________________________ so, c=8 ______________________________________________________ give to 2. ______________________________________________________ =a+b+8=21 ______________________________________________________ put (+8) into right side, turn to(-8) ______________________________________________________ =a+b=21-8 5.=a+b=13 =13-b=a/13-a=b ______________________________________________________ mix 5. (a+b) into 4.(a+b) ______________________________________________________ =(13-b)*b=42/(13-a)*a=42 =13*b-b*b=42/13*a-a*a=42 ______________________________________________________ cross 2b/2a (because one+one-) and see 4. so,a,b>0 that a,b=6,7
其他解答:
Do your * = x ? (a*b)/a+b+c=2 (a*b) / 21 = 2 (a*b) = 42 c*c=a*b*1.5+1 c*c = 42 x 1.5 +1 c*c = 64 c = 8 2009-02-03 12:36:50 補充： a+b+c = 21 a + b = 21-8 a + b = 13 a = 6 or 7 b = 6 or 7 because 6 + 7 = 13 6 x 7 = 42
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