close
標題:
Chem mole simple question
發問:
10.0 g iron ore sample contains iron(III) oxide. If the sample contains 3.3 g of iron, what is the percentage ny mass of iron(III) oxide in the sample? A 33% B 47% C 94% D100% I want a good answer, thank you
最佳解答:
what do you mean by "I want a good answer"? no one here will give you fake answers. mass of iron = 3.3 g no. of mole of iron = 3.3/55.8 = 0.0591 mole formula of iron(III) oxide : Fe2O3 mole ratio of Fe:Fe2O3 = 2:1 thus no. of mole of Fe2O3 = 0.059/2 = 0.0296 mole molar mass of Fe2O3 = 55.8x2 + 16x3 = 159.6 g/mol mass of iron(III) oxide = 0.0296 x 159.6 = 4.724 g percentage by mass = mass of analyte / total mass = 4.724/10 = 47.2%
其他解答:
3.3 g of iron|||||3.3g of iron(III)oxide or iron?
Chem mole simple question
發問:
10.0 g iron ore sample contains iron(III) oxide. If the sample contains 3.3 g of iron, what is the percentage ny mass of iron(III) oxide in the sample? A 33% B 47% C 94% D100% I want a good answer, thank you
最佳解答:
what do you mean by "I want a good answer"? no one here will give you fake answers. mass of iron = 3.3 g no. of mole of iron = 3.3/55.8 = 0.0591 mole formula of iron(III) oxide : Fe2O3 mole ratio of Fe:Fe2O3 = 2:1 thus no. of mole of Fe2O3 = 0.059/2 = 0.0296 mole molar mass of Fe2O3 = 55.8x2 + 16x3 = 159.6 g/mol mass of iron(III) oxide = 0.0296 x 159.6 = 4.724 g percentage by mass = mass of analyte / total mass = 4.724/10 = 47.2%
其他解答:
3.3 g of iron|||||3.3g of iron(III)oxide or iron?
此文章來自奇摩知識+如有不便請留言告知
文章標籤
全站熱搜
留言列表
