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標題:

數學求教: 3x+3-3x=3 求x

發問:

Hi, 如題, 3x+3-3x=3 求x 怎列算式? Thx a lot! 更新: Hi, 其實條問題係咁: The sum of three consecutive numbers minus three times the smallest number equals three. Find the three numbers. 請幫忙:

• 一題簡單複數 - z ge位置
• 打X你即是甚麼= =？
• Undetermined coefficients@1@

 

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最佳解答:

您好，我是 lop，高興能解答您的問題。 Let the smallest number be x , then the other two numbers are (x+1) and (x+2) . x + (x+1) + (x+2) - 3x = 3 3x + 3 - 3x = 3 3 = 3 Because 3 ≡ 3 , so x can be any number , for example we take x = 19 , then the sum of three consecutive numbers = 19 + 20 + 21 = 60 , three times the smallest number = 3(19) = 57 , the sum of three consecutive numbers minus three times the smallest number = 60 - 57 = 3 , correct . Answer : x can be any number .

其他解答:

其實 x 可以任何數，因為係咪都會約左... e.g. sub x=1 3(1)+3-3(1)=3 3-3+3=3 3=3 sub x=2 3(2)+3-3(2)=3 6+3-6=3 6-6+3=3 3=3 . . . sub x=999 3(999)+3-3(999)=3 2997+3-2997=3 2997-2997+3=3 3=3|||||Let x be 0, Change 3x +3 -3x =3 to 3×0 +3 -3×0 =3 頭尾兩個3×0因為係正同負所以可以刪去，咁就會得番： 3=3 所以x=0|||||3x + 3 = 3x + 3 Hence there are infinite many solutions for x is real.