標題:
a-maths!!!
發問:
最佳解答:
! a - b !^2 = (a - b)(a - b) = aa - ab - ba + bb = aa - 2ab + bb = !a!^2 - 2!a!!b!cos@ + !b!^2 bi) ! a - b !^2 = 3 - 2 sqrt(3) (2)cos30 + 4 = 7 - 6 = 1 ! a - b ! = 1 ii) ! a - b !^2 = 3 - 2 sqrt(3) (2)cos150 + 4 = 7 + 6 = 13 ! a - b ! = sqrt(13), 根 13 唔係好難,好基本,你應該識
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話我運吉? 10 個負評你應得!
a-maths!!!
發問:
此文章來自奇摩知識+如有不便請留言告知
點做a? http://www.uwants.com/attachments/day_070813/20070813_61f6a25adbab0045e9c4p9xCxRWF2QGv.jpg最佳解答:
! a - b !^2 = (a - b)(a - b) = aa - ab - ba + bb = aa - 2ab + bb = !a!^2 - 2!a!!b!cos@ + !b!^2 bi) ! a - b !^2 = 3 - 2 sqrt(3) (2)cos30 + 4 = 7 - 6 = 1 ! a - b ! = 1 ii) ! a - b !^2 = 3 - 2 sqrt(3) (2)cos150 + 4 = 7 + 6 = 13 ! a - b ! = sqrt(13), 根 13 唔係好難,好基本,你應該識
其他解答:
話我運吉? 10 個負評你應得!
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