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me有條math唔識,but已知答案,希望有位仁兄教教點例,題目如下:a two-digit number,the units digit is greater than the tens digit by 3.if the tens digit and the units digit of the number are interchanged,the sum of the number obtained and original number is 121.Find the numbers.翻釋如下:雙位數字，個位大於十位數的3，如果十位數和個位數字的互換，的總和後所得的數字和原來的數是121.A : 47,74 顯示更多 me有條math唔識,but已知答案,希望有位仁兄教教點例,題目如下: a two-digit number,the units digit is greater than the tens digit by 3.if the tens digit and the units digit of the number are interchanged,the sum of the number obtained and original number is 121.Find the numbers. 翻釋如下: 雙位數字，個位大於十位數的3，如果十位數和個位數字的互換，的總和後所得的數字和原來的數是121. A : 47,74
最佳解答:
3. In a two-digit number, the units digit is greater than the tens digit by 3. If the tens digit and the units digit of the number are interchange d, the sum of the number obtained and the original number is 121. Fin d the two numbers. Let t be tens digit and u be units digit, then u=t+3 Value of the original number = 10t+u Value of the number formed by interchanging the digits= 10u+t Sum of the two numbers=10t+u+10u+t=121 11u+11t=121 u+t=11 As u=t+3, u+t=t+3+t=11 2t+3=11 t=4 u=t+3=7 Therefore the two numbers are 47 and 74.
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我有條Math唔識,希望有人例條式比me就得!發問:
me有條math唔識,but已知答案,希望有位仁兄教教點例,題目如下:a two-digit number,the units digit is greater than the tens digit by 3.if the tens digit and the units digit of the number are interchanged,the sum of the number obtained and original number is 121.Find the numbers.翻釋如下:雙位數字，個位大於十位數的3，如果十位數和個位數字的互換，的總和後所得的數字和原來的數是121.A : 47,74 顯示更多 me有條math唔識,but已知答案,希望有位仁兄教教點例,題目如下: a two-digit number,the units digit is greater than the tens digit by 3.if the tens digit and the units digit of the number are interchanged,the sum of the number obtained and original number is 121.Find the numbers. 翻釋如下: 雙位數字，個位大於十位數的3，如果十位數和個位數字的互換，的總和後所得的數字和原來的數是121. A : 47,74
最佳解答:
3. In a two-digit number, the units digit is greater than the tens digit by 3. If the tens digit and the units digit of the number are interchange d, the sum of the number obtained and the original number is 121. Fin d the two numbers. Let t be tens digit and u be units digit, then u=t+3 Value of the original number = 10t+u Value of the number formed by interchanging the digits= 10u+t Sum of the two numbers=10t+u+10u+t=121 11u+11t=121 u+t=11 As u=t+3, u+t=t+3+t=11 2t+3=11 t=4 u=t+3=7 Therefore the two numbers are 47 and 74.
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